Integrand size = 8, antiderivative size = 42 \[ \int \cot ^5(a+b x) \, dx=\frac {\cot ^2(a+b x)}{2 b}-\frac {\cot ^4(a+b x)}{4 b}+\frac {\log (\sin (a+b x))}{b} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3554, 3556} \[ \int \cot ^5(a+b x) \, dx=-\frac {\cot ^4(a+b x)}{4 b}+\frac {\cot ^2(a+b x)}{2 b}+\frac {\log (\sin (a+b x))}{b} \]
[In]
[Out]
Rule 3554
Rule 3556
Rubi steps \begin{align*} \text {integral}& = -\frac {\cot ^4(a+b x)}{4 b}-\int \cot ^3(a+b x) \, dx \\ & = \frac {\cot ^2(a+b x)}{2 b}-\frac {\cot ^4(a+b x)}{4 b}+\int \cot (a+b x) \, dx \\ & = \frac {\cot ^2(a+b x)}{2 b}-\frac {\cot ^4(a+b x)}{4 b}+\frac {\log (\sin (a+b x))}{b} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.26 \[ \int \cot ^5(a+b x) \, dx=\frac {\cot ^2(a+b x)}{2 b}-\frac {\cot ^4(a+b x)}{4 b}+\frac {\log (\cos (a+b x))}{b}+\frac {\log (\tan (a+b x))}{b} \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.93
method | result | size |
derivativedivides | \(\frac {-\frac {\cot \left (b x +a \right )^{4}}{4}+\frac {\cot \left (b x +a \right )^{2}}{2}-\frac {\ln \left (\cot \left (b x +a \right )^{2}+1\right )}{2}}{b}\) | \(39\) |
default | \(\frac {-\frac {\cot \left (b x +a \right )^{4}}{4}+\frac {\cot \left (b x +a \right )^{2}}{2}-\frac {\ln \left (\cot \left (b x +a \right )^{2}+1\right )}{2}}{b}\) | \(39\) |
parallelrisch | \(\frac {-\cot \left (b x +a \right )^{4}+2 \cot \left (b x +a \right )^{2}+4 \ln \left (\tan \left (b x +a \right )\right )-2 \ln \left (\sec \left (b x +a \right )^{2}\right )}{4 b}\) | \(47\) |
norman | \(\frac {-\frac {1}{4 b}+\frac {\tan \left (b x +a \right )^{2}}{2 b}}{\tan \left (b x +a \right )^{4}}+\frac {\ln \left (\tan \left (b x +a \right )\right )}{b}-\frac {\ln \left (1+\tan \left (b x +a \right )^{2}\right )}{2 b}\) | \(57\) |
risch | \(-i x -\frac {2 i a}{b}-\frac {4 \left ({\mathrm e}^{6 i \left (b x +a \right )}-{\mathrm e}^{4 i \left (b x +a \right )}+{\mathrm e}^{2 i \left (b x +a \right )}\right )}{b \left ({\mathrm e}^{2 i \left (b x +a \right )}-1\right )^{4}}+\frac {\ln \left ({\mathrm e}^{2 i \left (b x +a \right )}-1\right )}{b}\) | \(77\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 83 vs. \(2 (38) = 76\).
Time = 0.27 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.98 \[ \int \cot ^5(a+b x) \, dx=\frac {{\left (\cos \left (2 \, b x + 2 \, a\right )^{2} - 2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \log \left (-\frac {1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac {1}{2}\right ) - 4 \, \cos \left (2 \, b x + 2 \, a\right ) + 2}{2 \, {\left (b \cos \left (2 \, b x + 2 \, a\right )^{2} - 2 \, b \cos \left (2 \, b x + 2 \, a\right ) + b\right )}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 66 vs. \(2 (32) = 64\).
Time = 0.31 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.57 \[ \int \cot ^5(a+b x) \, dx=\begin {cases} \tilde {\infty } x & \text {for}\: a = 0 \wedge b = 0 \\x \cot ^{5}{\left (a \right )} & \text {for}\: b = 0 \\\tilde {\infty } x & \text {for}\: a = - b x \\- \frac {\log {\left (\tan ^{2}{\left (a + b x \right )} + 1 \right )}}{2 b} + \frac {\log {\left (\tan {\left (a + b x \right )} \right )}}{b} + \frac {1}{2 b \tan ^{2}{\left (a + b x \right )}} - \frac {1}{4 b \tan ^{4}{\left (a + b x \right )}} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.90 \[ \int \cot ^5(a+b x) \, dx=\frac {\frac {4 \, \sin \left (b x + a\right )^{2} - 1}{\sin \left (b x + a\right )^{4}} + 2 \, \log \left (\sin \left (b x + a\right )^{2}\right )}{4 \, b} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 164 vs. \(2 (38) = 76\).
Time = 0.27 (sec) , antiderivative size = 164, normalized size of antiderivative = 3.90 \[ \int \cot ^5(a+b x) \, dx=-\frac {\frac {{\left (\frac {12 \, {\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} + \frac {48 \, {\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} + 1\right )} {\left (\cos \left (b x + a\right ) + 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) - 1\right )}^{2}} + \frac {12 \, {\left (\cos \left (b x + a\right ) - 1\right )}}{\cos \left (b x + a\right ) + 1} + \frac {{\left (\cos \left (b x + a\right ) - 1\right )}^{2}}{{\left (\cos \left (b x + a\right ) + 1\right )}^{2}} - 32 \, \log \left (\frac {{\left | -\cos \left (b x + a\right ) + 1 \right |}}{{\left | \cos \left (b x + a\right ) + 1 \right |}}\right ) + 64 \, \log \left ({\left | -\frac {\cos \left (b x + a\right ) - 1}{\cos \left (b x + a\right ) + 1} + 1 \right |}\right )}{64 \, b} \]
[In]
[Out]
Time = 16.32 (sec) , antiderivative size = 182, normalized size of antiderivative = 4.33 \[ \int \cot ^5(a+b x) \, dx=-x\,1{}\mathrm {i}+\frac {\ln \left ({\mathrm {e}}^{a\,2{}\mathrm {i}}\,{\mathrm {e}}^{b\,x\,2{}\mathrm {i}}-1\right )}{b}-\frac {4}{b\,\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}-1\right )}-\frac {8}{b\,\left (1+{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}-2\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\right )}-\frac {8}{b\,\left (3\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}-3\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}+{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}-1\right )}-\frac {4}{b\,\left (1+6\,{\mathrm {e}}^{a\,4{}\mathrm {i}+b\,x\,4{}\mathrm {i}}-4\,{\mathrm {e}}^{a\,6{}\mathrm {i}+b\,x\,6{}\mathrm {i}}+{\mathrm {e}}^{a\,8{}\mathrm {i}+b\,x\,8{}\mathrm {i}}-4\,{\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\right )} \]
[In]
[Out]